Question

un amestec de metan si butan are un continut de 81.051% carbon. Sa se stabileasca compozitia amestecului de alcani in procente de masa

Answer 1

notez  a molCH4 ,         cu M= 16g/mol
           b mol C4H10,     cu M= 58g/mol
100g amestec...contine.........81,051gC
(16a+58b)g............................(12a+48b)
1200a+4800b=1297a+4700b--->97a=100b---> a/b=100/97
a/b=1/0,97   raport molar, caruia ii corespunde raportul de masa 
m,CH4/m,C4H10= 1x16/0,97x58
in (16+56,3) g amestec.............16gCH4..................56,3gC4H10
       100g........................................X..................................Y
calculeaza x si y !!!!!!!