Question

Un amestec de metan si propina contine 13% hidrogen in procente masice. Care este compozitia procentuala masica a amestecului de hidrocarburi?

Answer 1

Ch4 a moli=> 16a g
C3H4 b moli => 40b g
16a + 40b......sunt 4a + 4b H2
100........13
13(16a+40b)=400a+400b
Calculand da b=1,6a
Am total: 16a + 40*1,6a= 80a
80a...16a CH4...64a C3H4
100...p1........p2
P1=20%
P2=80%

Answer 2

CH4 si C3H4
%H = mH/masa amestec*100
13=4x+4y/16x+40y * 100
400x+400y=208x+520y=>192x=120y=>x/y= 0,625 =>x/y=10/16
masa CH4 = 10*16 = 160 g
masa C3H4 = 16*40= 640 g
masa amestec = 160+640= 800 g
%CH4 = 160/800*100 = 20%
%C3H4 = 640/800 * 100 = 80%