Question

Un amestec de monoclorometan si diclorometan contine 74,7% clor. Care este compoziția procentuala masică a amestecului?

Answer 1

MCH3Cl=50,5g/mol
MCH2Cl2=85g/mol

50,5x+85y............................35,5x+71y 
100g..........................................74,7g

222,35x=750,5y => x/y = 750,5/222,35 = 150,1/44,5 = 30,02/8,9 = 15,01/4,45 = 3/0,89

m CH3Cl = 3*50,5 = 151,5g

m CH2Cl2 = 0,89*85=75,65g

m amestec = 151,5+75,65 = 227,15g

%CH3Cl = mCH3Cl/m amestec *100 = 75,65/227,15*100 = 33,3 %

%CH2Cl2 = 66,696 %