Question

Un amestec format din metan si propan conține 78.26%C. Care este volumul de aer consumat la arderea a 524 l amestec?

Answer 1

MCH4=16g/mol
MC3H8=44g/mol

16x+44y........................12x+36y
100..................................78,26

(16x+44y)78,26 = 1200x+3600y => 52,16x=156,56y => x/y = 156,56/52,16 = 3/1 => x=3y  => x=393L CH4

x+y=524 => 4y=524 => y=131 L C3H8

22,4L...2*22,4L
CH4 + 2O2 => CO2 + 2H2O + Q
393L......x L 

x=44,8*393/22,4 = 786 L O2

22,4L.....5*22,4L
C3H8 + 5O2 -> 3CO2 + 4H2O+ Q
131L.........x L

x=(5*22,4*131)/22,4 = 655 L O2

V O2 total = 655+786 = 1441 L O2

Vaer(20%O2) = 5*VO2 = 5*1441 = 7205 L aer