Question

Un automobil avand viteza initiala 36 km pe h se opreste intr.un interval de timp de 4 s . Calculati distanta parcursa .

Answer 1

$v=0\\v_o=36 km/h=10 m/s\\v=v_o+at<=>0=10+4a<=>a=-\frac{10}{4}=-2,5 m/s^2 \\d=v_ot+\frac{at^2}{2} =10*4-\frac{2,5*4^2}{2}=40- 20=20 m=>d=20 m$