Question

Un autoturism parcurge o distanta in patru zile.In prima zi parcurge cate 15 km pe ora mergand 7 ore;in a doua zi parcurge cu 25 km mai mult decat in prima zi,in a treia zi cu 95 km mai putin decat in primele doua zile la un loc,iar in a patra zi dublul nr 86.Sa se afle ce distanta a parcurs in cele patru zile?

Answer 1

1 zi=15×7=105
2 zi=105+25=130
3 zi=(105+130)-95=235-95=140
4 zi=86×2=172
total=105+130+140+172=235+140+172=375+172
=547

Answer 2

1.Aflam cati km a mers prima zi
15×7=105km
2.Aflam cati km aers a doua zi.
105+25=130km
3.Aflam cati km a mers a treia zi.
105+130-95=140km
235-95=140
4. Aflam cati km a mers a patra zi.
86×2=172 km
5.Aflam cati km a mers in cele patru zile.
105+130+140+172=567
235+140+172=567
395+172=567 km