Question

Un biciclist parcurge un drum in 4 zile.l zi parcurge 1/4 din drum si inca 10 km.ll zi parcurge 2/5 din rest.lll zi parcurge 1/3 din noul rest si inca 12km.lV zi parcurge ultimii 44 km.Care e lungimea drumului.

Answer 1

x=km drum
x/4+10=  1 zi
x-x/4-10=3x/4-10 rest
(3x/4-10)×2/5=3x/10-4 =a 2-a zi
3x/4-10-3x/10+4=(15x-6x)/20-6 = 9x/20-6 rest
(9x/20-6) x1/3+12=3x/20-2+12=3x/20+10 =a 3-a zi
x/4+10+3x/10-4+3x/20+10+44=x
x/4+3x/10+3x/20+60=x
15x+18x+9x+3600=60x
18x=3600
x=3600/18=200 km

1 zi        200x1/4+10=60 km
             200-60 =140 km
a2-a zi   140x2/5=56 km 
             140-56=84 km
a3-a zi    84x1/3+12=40 km
a4-a zi    84-40=44 km