Question

un calator parcurge in prima zi jumatate din drmul pe care-l avea de parcurs a doua zi parcurge 12%din rest iar in ultima zi parurge restul de 4,4km determinati lungimea drumului

Answer 1

I=1/2×d
II=12/100×rest
III=4,4km
Rezolvare: 1/2×d+12/100×(d-1/2×d)+4,4=d
1/2×d+12/100×1/2×d+4,4=d
d/2+12d/200+4,4=d ,Iar acum amplificam:
100d/200+12d/200+880/200=200d/200 / ×200
100d+12d+880=200d
112d+880=200d
880=200d-112d
880=88d
d=10 km
I=5km
II= 12/100×5=600/100=0,6 km
III=4,4 km