Question

Un calator parcurge in prima zi jumatate din lungimea drumului si inmca 1Km,a doua zi o treime din drum si inca 1 Km,iar in a treia zi ultimii 3 Km.Cati Km are drumul ?Rezolvare pentru cls a v a .

Answer 1

prima zi⇒y/2+1km;
a doua zi⇒y/3+1km;
a tria zi⇒ultimii 3 km;
⇒y/2+1km+y/3+1km+3km=y
⇒y/2+y/3+[1km+1km+3km]=y
⇒y/2+y/3+5km=y
⇒5km=y-]y/2+y/3]
⇒5km=y-[3y/6+2y/6]
⇒5km=y-5y/6
⇒5km=6y/6-5y/6
⇒5km=y/6
⇒y=6·5km⇒y=30km[are drumul];