Question

un compus organic B are raportul de masa C:H = 6:1. In urma analizei elementale cantitative a 1,27 g compus s-au obtinut 287 g AgCl. Stiind ca subst. nu contine oxigen si ca are masa moleculara 127 se cere:
formula moloeculara a subst. B

Answer 1

-deduc raportul molar din raportul de masa
nC:nH=6/12 : 1/1=> 0,5:1----> FORMULA BRUTA  (C0,5H)nClx
-deduc masa si moli de Clor din masa compusului AgCl ,care are M=143,5g/mol

143,5g AgCl.........35,5gCl
287g....................m= 71gCl;   niu(n)=71g/35,5g/mol= 2 molCl=x
-deduc formula moleculara din masa molara
127= 71gCl +n(6gC+1gH)---> n=8---> C4H8Cl2 diclorobutan