Question

Un corp cu masa m1= 800 Kg se afla la distanta r=0,25m de un alt corp cu masa m2=600 Kg. Sa se calculeze intensitatea campului gravitational intr-un punct situat la r1=0,20 m de m1 si la distanta r2=0,15 m de m2.​

Answer 1

$\Gamma^2=\Gamma_1^2+\Gamma_2^2+2\Gamma_1\Gamma_2cos\alpha\\\alpha=90^o=>cos\alpha=cos90^o=0\\\Gamma^2=\Gamma_1^2+\Gamma_2^2=\frac{km_1}{r_1^2}+\frac{km_2}{r_2^2}=\frac{km_2r_1^2+km_1r_2^2}{r_1^2+r_2^2}=\frac{k(m_2r_1^2+m_1r_2^2)}{r_1^2+r_2^2}=6,67*10^{-11}*\frac{600*0,2^2+800*0,15^2}{0,2^2+0,15^2}=6,67*10^{-11}*\frac{24+18}{0,0625}=6,67*10^{-11}*672=448,224*10^{-10}=>\Gamma=\sqrt{448,224*10^{-10}}=21,17*10^{-5} N/kg$