Question

un corp porneste de pe loc si ajunge sa aiba viteza de 50 km/h in 5 s .Sa se calculeze acceleratia miscarii si distanta parcursa​

Answer 1

$\bf v=50\dfrac{km}{h} =50 \cdot \dfrac{1000m}{3600s} =\dfrac{50000m}{3600s} \cong 13,9 \dfrac{m}{s}$

$\bf \Delta t = 5\,s$

$\bf v=\dfrac{\Delta d}{\Delta t} \implies \Delta d =v \cdot \Delta t$

$\bf \implies \Delta d = 13,9\dfrac{m}{s} \cdot 5 s= \boxed{\boxed{\bf 69,5 \, m}}$

$\bf a=\dfrac{\Delta v}{\Delta t} =\dfrac{13,9\dfrac{m}{s} }{5\, s} =\dfrac{13,9}{5} \dfrac{m}{s^2} =2,78\dfrac{m}{s^2}$

$\bf \implies \boxed{\boxed{\bf a=2,78\dfrac{m}{s^2} }}$

Bafta! :)

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