Question

Un corp strabate o distanta d=50 m intr un timp t=4 s, intr o niscare unifirm variata, stiind ca initial corpul se afla in repaus, sa se afle :
1: viteza finala
2: acceleratia miscarii
3: viteza corpului la jumatatea distantei

Answer 1

2)
S=a*t²/2 de unde
a=2*S/t²=2*50/16=6,25m/s²
1)
v=a*t=6,25*4=25m/s
3)
v=√(2*a*d) unde d=s/2
v=√(2*6,25*25)=17,7m/s
Vacaanta placuta!