Question

Un fermier a arat in cinci zile cei 168m de teren pe care ii poseda.in prima zi a arat 3/8 din suprafata,a doua zi cu 2/8 mai putin decat in prima zi,air a treia zi cu1/8 mai mult decat in a doua zi, iar a patra si a cincea zi restul,in mod egal.
Cati m a arat fermierul in fiecare dintre ce cinci zile?

Answer 1

total teren=168 m
3/8=168:8x3=63 m in prima zi
2/8=168:8x2=42
63-42=21 m a doua zi
1/8+1/8=2/8=21+21=42 a treia zi
3/8+1/8+2/8=6/8
8/8-6/8=2/8 in zilele 4 si 5
in ziua 4=1/8
in ziua 5=1/8

Answer 2

|---|---|---| (1zi)
|---| (2zi)
|---|---| (3zi)
168:8=21 a doua zi
21*3=63 prima zi
21*2=42 treia zi
168-21-63-42=42
42:2=21 a patra zi
42-21=21 a cincea zi