Question

un gospodar are 404 pasari: gaini, rate, gaste si curci . gaini sunt 140. cate pasari sunt de fiecare fel, daca diferenta dintre numarul ratelor si a gastelor este 19, iar curci sunt de 3 ori mai putine decat gaste.

Answer 1

a=gaini
b=rate
c=curci
d=gaste

a+b+c+d=404
a=140

140+(b+c+d)=404
b+c+d=404-140
b+c+d=264

b-d=19⇒b=19+d⇒b=19+3c
d=3c

19+3c+c+3c=264
7c+19=264
7c=264-19
7c=245
c=245:7
c=35

d=3c
d=3*35
d=105

b=19+3c
b=19+3*35
b=124

Verificare : 35+105+124=264
                  140+264=404

Answer 2

404 - 140 = 264 pasari
gaini + r + g + c = 404
r - g = 19
r = g + 19
3c = g
r = 3c + 19
3c + 19 + 3c + c = 264
7c = 264 - 19 
7c = 245
c = 35 
g = 3 * 35
g = 105
r + 35 + 105 = 264
r = 264 - 140
r = 124
124 rate + 105 gaste + 35 curci + 140 gaini = 404 pasari