Question

un intreg 5 supra 12 totul la puterea -1 =?

Answer 1

Răspuns:

$(1\frac{5}{12} )^{-1} = (\frac{1*12+5}{12} )^{-1} = (\frac{17}{12} )^{-1} = \frac{1}{(\frac{17}{12})^{1}} = \frac{1}{1} * \frac{12}{17} = \boxed{\frac{12}{17} }$

Answer 2

Răspuns:

1 intreg 5/12=(1·12+5)/12=17/12

(17/12)⁻¹=12/17

se inversează fractia si se ridica la puterea 1