Question

(un intreg1/3-5)²:7/2+[0,(1)]⁰ ​

Answer 1

Răspuns:

Explicație pas cu pas:

(un intreg1/3-5)²:7/2+[0,(1)]⁰ =

(4/3 - 5)^2 : 7/2 + 1 =

(4-15  /  3)^2 : 7/2 + 1 =

(-11/3)^2 : 7/2 + 1 =

121/9 x 2/7 + 1 =

242/63 + 1 =

3si53/63 + 1 =

4 si 53/63.

Answer 2

$\it \Big(1\dfrac{1}{3}-5\Big)^2:\dfrac{7}{2}+\[[0,(1)]^0=\Big(-3\dfrac{2}{3}\Big)^2\cdot\dfrac{2}{7}+1=\Big(\dfrac{11}{3}\Big)^2\cdot\dfrac{2}{7}+1=\\ \\ \\ =\dfrac{121}{9}\cdot\dfrac{2}{7}+1=\dfrac{242}{63}+1=3\dfrac{53}{63}+1=4\dfrac{53}{63}$