Question

Un monoester saturat contine 27,59% O2.Numarul izomerilor esteri cu activitate optica va fi:
R: 10

Answer 1

CnH2nO2 = 14n+32

%O=mO/M*100 => 27,59=32/14n+32*100 => 3200=386,26n+882,88 => 386,26n=2317,12 => n=6

CH3-CO-O-CH2-CH2-CH2-CH3

CH3-CO-O-CH2-CH(CH3)-CH3 => 2¹=2

CH3-CO-O-CH(CH3)-CH2-CH3 => 2¹=2

CH3-CO-O-CH(CH3)2-CH3 => 2¹=2

CH3-CH2-COO-CH2-CH2-CH3

CH3-CH(CH3)-COO-CH2-CH3 => 2¹=2

CH3-CH2-COO-CH(CH3)-CH3 => 2¹=2

2+2+2+2+2=10 esteri cu activitate optica.. nu sunt sigur..