Question

Un muncitor a realizat in 3 zile 90 de piese. In a doua zi el a realizat cu 5 pises mai mault decat in prima iar in a treia zi cu 5 piese mai mault decat in a doua zi.Cate piese s-au facut in prima zi Repede va rog

Answer 1

$a, b,c = cele~trei~zile$
a |____|
b |____|5|
c |____|5|5|

$a+a+5+a+5+5+=90~ zile$
$3a+15=90$
$3a=90-15$
$3a=75$
$a=75:3$
$a=25$
$b=25+2=30$
$c=25+10=35$
$V: 25+30+35=90$