Question

un muncitor executa in 3 zile un numar de piese astfel: in prima zi 1/9 din numarul de piese, a doua zi 1/6 din rest si inca 2 piese , iar in a treia zi restul de 18 piese .Aflati cate piese executa muncitorul in total si cate piese a facut in fiecare zi

Answer 1

1/9×n+1/6×(n-1/9×n)+20=n

1/9×n+1/6×8/9×n+20=n

n-1/9×n-8/54×n=20

n×(54/54-6/54-8/54)=20

n×40/54=20

n=20×54/40

n=27 piese

1/9×27=27/9=3 piese in prima zi

1/6×24+2=24/6+2=6 piese in a doua zi

Sper ca ti-am fost de ajutor!