Question

Un numar mai mic decat 2000,împartit la 30,40,50,da resturile 28,38,48.Aflati numarul.

Answer 1

n<2000
n=30xc1+28=40xc2+38=50xc3+48
n+2=30xc1+30=40xc2+40=50xc3+50
n+2=30(c1+1)=40(c2+1)=50(c3+1)
n+2=M [30,40,50]
n+2=M 600
n+2={600,1200,1800}
n={598,1198,1798}