Question

un numar natural da restul 23 la impartirea cu 28.aflati restul impartirii aceluiasi nr. la 7

Answer 1

x:28=c rest 23⇒  x=28c+23⇒ x+5=28c+23+5
x:7=c  rest....⇒   x=7c+...  ⇒x+5=7 c+5+2⇒

x+5=M[28,7]
28=2²·7
7=7
[28,7]=28
M[28]={0,28,56,84,140}
x+5=28
x=28-3=25 nu e bun
x+5=56
x=56-5
x=51
51:28=1 rest 23
51:7=7 rest 2