Question

Un obiect liniar si luminos se asaza perpendicular pe axa optica a unei lentile cu f mic=6 cm la distanta de 4 cm fata de aceasta.Calculati distanta la care se formeaza imaginea fata de lentila si marirea liniara transversala.

Answer 1

x1=-4 cm (distanta obiect-lentila)

f=6 cm

x2=?

$\frac{1}{x2} - \frac{1}{x1} = \frac{1}{f}$

$\frac{1}{x2} + \frac{1}{4} = \frac{1}{6}$

$\frac{4 + x2}{4 \times x2} = \frac{1}{6}$

$6(4 + x2) = 4 \times x2$

$24 + 6x2 = 4 \times x2$

$24 + 2x2 = 0$

$24 = - 2x2$

$x2 = - 12$

beta (marirea liniara)= x2/x1

beta= -12/-4= 3 => imagine virtuala