Question

Un oxid contine 70,37% nemetal si are masa molara M=54 g/mol. Determinati formula si denumirea oxidului.
a) concentratia procentuala a solutiei obtinuta prin introducerea a 1,08g oxid in 49,56 H2O la cald.
FeS2+a⇒Fe2O3+b
b+a⇒SO3
SO3+H2O⇒d
d+NaCl⇒Na2SO4+e
e+Zn⇒ZnCl2+f degaja gaz
f+a⇒H2O

Answer 1

-aflu formula oxidului
100g oxid..........70,37gN.......29,36gO
54g..................x= 38g...................y= 16g
16g este masa unui atom O ; 38/2 g=19g este masa unui atom F----> F2O( oxid de fluor?)

- c/100= md/ms
md=1,08
ms.= md+mapa=> 1,08+49,56---> c=1,08x100/ 50,64    calculeaza !

2FeS2 +11/2O2--->Fe2O3 +4SO2
SO2+1/2O2---> SO3
SO3+H2O---> H2SO4
H2SO4+2NaCl---> Na2SO4 +2HCl
2HCl+Zn---> ZnCl2 +H2↑
H2 +1/2O2---->H2O