Question

Un pătrat are perimetrul de 4radical2. Aria este de.....?

Answer 1

P=4L
4√2=4L⇒L=√2
A=L²=(√2)²=2 cm²

Answer 2

$\left\| \begin{array}{ll} P_{\square} = 4l\ \\ P_\square = 4\sqrt2\end{array} \right | \Rightarrow 4l = 4\sqrt2 \Rightarrow l = \sqrt2 \\\\ \\ \left\| \begin{array}{ll} A_{\square} = l^2\ \\ l = \sqrt2\end{array} \right | \Rightarrow A_\square =(\sqrt2)^2 \Rightarrow \boxed{\boxed{A_\square = 2}}$