Question

un pic de ajutor va rog, nu inteleg derivatele compuse

Answer 1

$\it (\sqrt x)' = \dfrac{1}{2\sqrt x} \\ \\ \\ (\sqrt u)' = \dfrac{u'}{2\sqrt u} \\ \\ \\ (\sqrt{x^2+3})' = \dfrac{(x^2+3)'}{2\sqrt{x^2+3}} =\dfrac{2x}{2\sqrt{x^2+3}} = \dfrac{x}{\sqrt{x^2+3}}$