Question

Un recipient contine 3,012 * 10 la puterea 23 molecule de HCl. Afla :
a) masa gazului exprimata in kg
b)volumul HCl (c.n)
c) volumul HCl la 3 atm si 27 grade

Answer 1

a) MHCl=36.5g/mol
1 mol HCl.............6.022*10^23 molecule HCl
x=0.5 moli HCl    3.012*10^23 molecule HCl

n=m/M==>m=n*M=0.5*36.5=18.25g=0.01825 kg HCl

b) n=V/Vmolar==>V=n*Vmolar=0.5*22.4=11.2 L HCl

n=nr moli
V=volumul, L
Vmolar= volumul unui mol de gaz in c.n=22.4L

c) T=273+27=300K
p=3 atm

pV=nRT==>V=nRT/p=0.5*0.082*300/3=4.1 L HCl