Question

Un recipient contine 3,012 10²³ molecule HCL. Afla:
a) masa gazului exprimata in kg
b) volumul HCL (c.n)
c) volumul HCL la 3 atm si 27°C

Answer 1

M,HCl= 36,5g/mol
Vm= 22,4 l/mol

n(niu) =N/N,a= 3,012x10²³/6,023x10²³=0,5mol HCl
m=nxM=0,5X36,5g=18,25g= 0,01825kg HCl
V=nxVm= 0,5x22,4 l= 11,2 l
pV=nRT--> 3xV=0,5x0,082x(273+25)................calculeaza V !!!!