Question

un recipient contine 3,012 ori 10 la puterea 23 molec. HCL.afla:
a)masa gazului exprimata in kg
b) volum HCL(c.n)
c)vol HCL la 3 atm si 27 grade C

Answer 1

a)1 mol = 6,022 * 10 la 23 molec
x moli = 3,012 * 10 la 23 molec
x = 0,5 moli HCl = 18,25 g HCl = 0,01825 kg HCl
b)1 mol = 22,4 litri in conditii normale
0,5 moli = x litri        x  = 11,2 litri HCl
c)pV=nr moli*R*T=>p=R=nr moli*T/p=0,5*0,082*300/3=>Volumul=4,1 litri