Question

Un resort are constanta de elasticitate egala cu 100 N/m. Determinati masa corpului, care fiind suspendat de resort se alungeste cu 9,8 cm.

Answer 1

k= 100 N/m
(delta)L=9,8cm=0,098 m

Fe=G=mg
Fe=k*(delta)L

=> mg=k*(delta)L => m= (k*(delta)L)/g = (100*0,098)/10 => m=0,98 kg.

Answer 2

Se da:
k=100N/m
x=9,8cm=0,098m
m=?kg

Formule:
Fel=k*x
G=k*x
m*g=k*x
m=k*x/g

Calcule:
m=100*0,098/9,8=1kg