Question

Un resort are constanta elastica k=200n/m si se alungeste cu 2 cm ,daca suspendam de el un corp de masa necunoscuta .Daca g=10n/kg ,calculati masa.Ajutati ma urgent ,va roogggg ,dau cel mai bun raspuns

Answer 1

$K=200\frac{N}{m}, \Delta l=2 cm, m=?$
$F_d=K\Delta l\implies m=\frac{K\Delta l}{g}\\m=\frac{200N/m\cdot 0,02 m}{10 N/kg}=\frac{4N}{10N/kg}=4N\cdot \frac{kg}{10N}=0,4kg$