Question

Un romb Abcd are AC=18cm , BD=20cm si perimetrul de 104cm . Aria rombului ? Inaltimea rombului

Answer 1

Arie= $\frac{D1*d2}{2} = \frac{AC*BD}{2} = \frac{48cm*20cm}{2}=480cm^2$
Perimetru=4 *l =>l=$\frac{P}{4} = \frac{104cm}{4} =26cm$
h-inaltimea
A romb= latural*h =>h=$\frac{A}{l}$
h=[tex] \frac{480cm^2}{26cm} = 240/13