Question

un romb are diagonalele direct proportionale cu numerele 8 si 10 si aria egala cu 160 cm .Diagonala mica a rombului are lungimea de?

Answer 1

d₁ /8 = d₂ /10=k

d₁ /8=k => d₁=8*k

d₂ /10=k => d₂=10*k

A=(d₁*d₂):2=160 cm

d₁*d1=160*2

8k*10k=320

80k²=320

k²=320:80

k²=4   => k=√4  => k=2

d₁=8*2=16 cm  (diagonala mica)

d₂=10*2=20 cm