Question

Un romb are perimetrul de 32 cm si o diagonala cu lungimea de 8 cm . Atunci cealalalta diagonala are lungimea de ?

Answer 1

ABCD romb ⇒ AC⊥BD (diagonale)⇒ AC∩BD= O ⇒ ΔAOB = Dr ⇒TEOREMA LUI PITAGORA ⇒ab=32÷4=8 ⇒ AO²= AB²- BO² ⇒ AO²= 64-16=48 ⇒ AO=4√3 
DIAG= 2AO = 8√3 cm