Question

Un tetraedru regulat cu muchia 6 cm are înălțimea...​

Answer 1

$a_{t}=\frac{l\sqrt{3}}{2}=\frac{6\sqrt{3}}{2}=3\sqrt{3}~ cm \\\\ a_b=\frac{a_t}{3}=\frac{3\sqrt{3}}{3}=\sqrt{3}~ cm\\\\ h²=a_t²-a_b²\\ h²=(3\sqrt{3})²-\sqrt{3}²\\ h²=9×3-3\\ h²=27-3\\ h²=24\\ h=2\sqrt{6}~ cm$