Question

Un trapez are baza mare 3a+c, baza mica 2c+3b, unde a,b,c>0, si a+b+c=12. Inaltimea trapezului este egala cu 12. Determinați aria sa.
mulțumesc anticipat!​

Answer 1

Răspuns:

$trapez$

$B=3a+c$

$b=2c+3b$

$a+b+c=12$

$h=12$

$A=?$

___________

$A=\frac{(B+b)*h}{2} =\frac{(3a+c+2c+3b)*12}{2} =\frac{(3a+3c+3b)*12}{2} =\frac{3*(a+c+b)*12}{2} =\frac{3*12*12}{2} =216$

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