Question

Unghiurile AOB,BOC,COA sunt trei unghiuri in jurul punctului O,astfel incat m(AOB)=4x+43°,m(BOC)=100°-x si m(COA)=x+41°.Calculati masurile unghiului

Answer 1

m(AOB)+m(BOC)+m(Coa)=360 grade
4x+43grade+100 grade-x+x+41grade=360
4x184 grade=360grade
4x=360-184
x=176/4
x=44
m(AOB)=4x+43grade=4·44+43=219 grade
m(BOC)=100-x=100-44=56 grade
m(COA)=x+41=44+41=85 grade
219+56+85=360