Question

Unghiurile AOB,BOC,COD,AOD SUNT unghiuri in jurul unui punct O,astfel incat:
a) m (AOB)=X grade
B) m (BOC)=2x grade+10 grade
C) m(COD)=3x grade - 5 grade
D) m (AOD)= 4x grade + 5 grade

Answer 1

x+2x+10+3x-5+4x+5=360
10x+10=360
10x=350
x=35°
a) m (AOB)=35°
b) m (BOC)=2*35°+10° =80°
 c) m(COD)=3*35° - 5°=100°
d) m (AOD)= 4*35° + 5°=145°