Question

URGEEEEEEENT,VA ROOOOOOG MUUUUUUUULT! Determinati nr ionilor de potasiu ( K) dintr-un amestec echimolecular ce contine clorat de potasiu ( KClO3) si
clorura de potasiu (KCl) cu masa 19, 7g.

Answer 1

M,KClO3=  (39gK + 35,5gCl+3x16gO)/mol= 122,5g/mol
M,KCl=(39gK+35,5gCl)=74,5g/mol
- notez cu a nr. moli de clorat si de clorura din amestec
a,molx(122,5+74,5)g/mol=19,7-g--> a= 0,1mol din fiecare sare
-cum in fiecare mol de sare se gaseste cate 1 mol de ion potasiu,sunt, in total, 0,2mol ioniK=
-1MOL ion.........are.....6,023x10²³ioni
  0,2mol................................N= 0,2x6,023X10²³ioni potasiu   calculeaza!