Question

URGEEEEEENNTTTTT!!!

PLS ​

Answer 1

Explicație pas cu pas:

a)

5483 = 5×1000 + 4×100 + 8×10 + 3

=>

a = 5

b = 4

c = 3

b)

2000 + 100a + 10a + 6 + 10a + 5 + a = 2858

121a = 2858 - 2011

121a = 847

a = 7

c)

$100x + 10y + z + 10x + y + x = 412$

$111x + 11y + z = 412$

$111x = 412 - (11y + z)$

$0 \leqslant y \leqslant 9 \iff 0 \leqslant 11y \leqslant 99 \\ 0 \leqslant z \leqslant 9 \iff 0 \leqslant 11y + z \leqslant 108 \\ 412 - 108 \leqslant 412 - (11y + z) \leqslant 412 \\ 304 \leqslant 412 - (11y + z) \leqslant 412 \\ 304 \leqslant 111x \leqslant 412 \implies \bf x = 3$

$11y + z = 79 \iff 11y = 79 - z$

$0 \leqslant z \leqslant 9 \iff 70 \leqslant 79 - z \leqslant 79 \\ 70 \leqslant 77y \leqslant 79 \implies \bf y = 7$

$z = 79 - 77 \implies \bf z = 2$

x = 3, y = 7, z = 2