Question

Urgeeeent. va rog......​

Answer 1

primul rand

(1)K2e- (2)L8e- (3)M18e- (4)N2e-

=> Z = 2+8+18+2 = 30

=> 1s2 2s2 2p6 3s2 3p6 4s2 3d10

nr. orbitali = 4 tip s + 2x3 tip p + 5 tip d = 15

nr. substraturi = 1s + 2s+ 2p+ 3s+ 3p +4s +3d = 7 substarturi

Z = 30

randul doi

avem Z = 20

(1)K2e- (2)L8e- (3)M10e-

=> 1s2 2s2 2p6 3s2 3p6 4s2

nr. orbitali = 4 tip s + 2x3 tip p = 10

nr. substraturi = 1s + 2s+ 2p+ 3s+ 3p +4s = 6 substarturi

randul trei

(1)K2e- (2)L8e- (3)M18e- (4)N18e- (5)O7e-

=> Z = 2+8+18+18+7 = 53

=> 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5

nr. orbitali = 5 tip s + 4x3 tip p + 2x5 tip d = 27

nr. substraturi = 1s + 2s+ 2p+ 3s+ 3p +4s +3d+ 4p+ 5s+ 4d+ 5p = 11 substarturi

Z = 53