Question

Urgeeent ca raman corigenta la chimie

Answer 1

1.

prezinta o grupare carboxil

2.

Fm = C7H12O3, avem 7x12 = 84g C si 12x1 = 12g H

raport C:H = 84:12 = 7:1

3.

(1) = tertiar  (2) = primar

4.

a.

CH3-CH2-C=CH-CH-COOH + Br2 --CCl4--> CH3-CH2-CBr-CHBr-CH-COOH

                 CH3   OH                                                         CH3          OH

b.

CH3-CH2-C=CH-CH-COOH + NaOH --> CH3-CH2-C=CH-CH-COONa + H2O

                 CH3   OH                                                   CH3   OH

5.

Fb = Fm/n

daca n = 3 (maxim posibil)

=> Fb = (C2,33H4O)n