Question

Urgennttt,va rog mult!

Answer 1

($(\sqrt{3}-\sqrt{2})^{2}   = \sqrt{3} ^{2} -2*\sqrt{3} *\sqrt{2} +\sqrt{2}^{2}  = 3-2\sqrt{6} +2$

($(\sqrt{3}+\sqrt{2})^{2}   = \sqrt{3} ^{2} +2*\sqrt{3} *\sqrt{2} +\sqrt{2}^{2}  = 3+2\sqrt{6} +2$

($(\sqrt{3} -\sqrt{2} )(\sqrt{3} +\sqrt{2} )=\sqrt{3} ^{2} -\sqrt{2} ^{2} =3-2$

rezultă $3-2\sqrt{6} +2+3-2+3+2\sqrt{6} +2$

se reduc $-2\sqrt{6}  cu   +2\sqrt{6}$

3+2+3-2+3+2=11