Question

Urgent ajutatima am nevoie

Answer 1

Răspuns:

Explicație pas cu pas:

4.

$2x^{2} +5x-3=0, 2x^{2} +6x-x-3=0,2x(x+3)-(x+3)=0,(x+3)(2x-1)=0, x_{1}=-3, x_{2}=\frac{1}{2}$

A={-3;1/2}, A∩{-3;3}={-3}

5.

x+3y=38

x-y=-6⇒3x-3y=-18, prin adunare 4x=20, x=5

5-y=-6, y=11