Question

Urgent am nevoie de acest exercitiu.​

Answer 1

(a+b+c+d)/4=10,25

b=a+1

c=b+1=a+1

(a+b+c)/3=13→(a+a+1+a+2)/3=13→3a+3=39→3a=36→a=12

→b=13→c=14

(12+13+14+d)/4=10,25→39+d=41→d=2

Fie d=lungimea drumului

d=1/7×d+1/6×d+2,5

42d/42=6d/42+7d/42+105/42

42d=13d+105

29d=105

d=105/29

In prima zi a parcurs 1/6×105/42 (fă tu calculul)

A doua nu cred că mi-a dat bine dar nu am alta idee de rezolvare