Question

Urgent am nevoie de rezolvarea problemei.

Answer 1

Lex=hυ₀=6,62*10⁻³⁴*6,63*10¹⁴=43,89*10⁻²⁰ J

Ecmax=hυ-Lex=6,62*10⁻³⁴*9,63*10¹⁴-43,89*10⁻²⁰= 63,75*10⁻²⁰-43,89*10⁻²⁰=19,86*10⁻²⁰  J

λ=c/υ=3*10⁸/9,63*10¹⁴=0,31*10⁻⁶=310 nm

p=h/λ=6,62*10⁻³⁴/0,31*10⁻⁶=21,35*10⁻²⁸ Ns

p=m*vmax=>vmax=p/m

hλ=Lex+m*vmax²/2=>m*vmax²/2=hλ-Lex=>vmax=√[2/m(hλ-Lex)]<=>p²/m²=2/m(hλ-Lex)<=>455,82*10⁻⁵⁶/m=2*19,86*10⁻²⁰<=>455,82*10⁻⁵⁶/m=39,72*10⁻²⁰=>m=455,82*10⁻⁵⁶/39,72*10⁻²⁰=11,47*10⁻³⁶ kg

vmax=p/m=21,35*10⁻²⁸/11,47*10⁻³⁶ =1,86*10⁸ m/s

e*Us=Ecmax=>Us=Ecmax/e=19,86*10⁻²⁰/1,6*10⁻⁹=1,241 V

pi=h/λ₀=hυ₀/c=6,62*10⁻³⁴*6,63*10¹⁴/3*10⁸=43,89*10⁻²⁰/3*10⁸=14,63*10⁻²⁸ Ns