Question

Urgent! am nevoie la h) si la j)​

Answer 1

Răspuns:

$h) \: (\frac{13}{5\sqrt{3} } +\frac{9}{3\sqrt{3} }^{(3} )-(\frac{33}{3\sqrt{2} }^{(3} -\frac{16}{4\sqrt{2} }^{(4} -\frac{7}{\sqrt{2} } )= (\frac{13}{5\sqrt{3} } +\frac{3}{\sqrt{3} })-(\frac{11}{\sqrt{2} }-\frac{4}{\sqrt{2} }-\frac{7}{\sqrt{2} } )=\frac{28}{5\sqrt{3} } -\frac{0}{\sqrt{2} } =\frac{28\sqrt{3} }{15} -0=\frac{28\sqrt{3} }{15}$

$j)\:(\frac{8}{\sqrt{10} }+\frac{30}{3\sqrt{10} }^{(3} +\frac{\sqrt{20} }{5} )-(\frac{4}{\sqrt{40} } +\frac{2\sqrt{10} }{3} -\frac{11}{2\sqrt{10} } )=(\frac{8}{\sqrt{10} }+\frac{10}{\sqrt{10} } +\frac{2\sqrt{5} }{5})-(\frac{4}{2\sqrt{10} } ^{(2} +\frac{2\sqrt{10} }{3} -\frac{11}{2\sqrt{10} } )=(\frac{18}{\sqrt{10} } +\frac{2\sqrt{5} }{5})-(\frac{2}{\sqrt{10} } +\frac{2\sqrt{10} }{3} -\frac{11}{2\sqrt{10} } )= \frac{18}{\sqrt{10} } +\frac{2\sqrt{5} }{5}-(-\frac{7}{2\sqrt{10} } +\frac{2\sqrt{10} }{3})$

$=\frac{9\sqrt{10} }{5} +\frac{2\sqrt{5} }{5} -(-\frac{7\sqrt{10} }{20} +\frac{2\sqrt{10} }{3} )=\frac{9\sqrt{10} }{5} +\frac{2\sqrt{5} }{5} -\frac{19\sqrt{10} }{60} =\frac{89\sqrt{10} }{60} +\frac{2\sqrt{5} }{5}$