Question

URGENT!!!

Calculați volumul de aer (20% oxigen) necesar arderii A 6,4g metanol in Conditii normale.

Answer 1

M,metanol= 32g/mol

niu=m/M= 6,4g/32g/mol= o,2mol

1mol.............1,5mol

CH3OH + 3/2O2----> CO2 + 2H2O

0,2mol..........x= 0,3mol

V,o2= niuxVm= 0,3molx22,4l/mol= 6,72 L

V,aer= 100x6,72/20 l=33,6 l      deoarece aerul contine 20% O2