Question

URGENT!! CORONITA!! un derivat dihalogenat aciclic contine 57,67% halogen ( fluor + clor). sa se determine formula moleculara si structurile posibile.

Answer 1

CnH2nFCl - formula generala
M=12n+2n+31+35,5=14n+67,5
M.............100%
71.........57,67%
M=7100/57,67=123,5
14n+67,5=123,5 => 14n=56 => n=4
C4H8FCl
FClCH-CH2-CH2-CH3
FClCH-CH(CH3)-CH3
CH3-CFCl-CH2-CH3 (izomeri optici)
FCH2-CH(Cl)-CH2-CH3 (izomeri optici)
FCH2-CCl(CH3)-CH3
ClCH2-CF(CH3)-CH3
FCH2-CH2-CH(Cl)-CH3 (izomeri optici)
ClCH2-CH2-CH(F)-CH3 (izomeri optici)
ClCH2-CH2-CH2-CH2F
ClCH2-CH(CH3)-CH2F (izomeri optici)
in jur de 15 izomeri