Question

Urgent!!! Dau coroana!!!

Answer 1

$\bf \dfrac{x-2}{(-1)^{2}+3\cdot(-2)} =\dfrac{(-5+7)\cdot(-2)^2}{(-2)^{3}}$

$\bf \dfrac{x-2}{1-6} =\dfrac{(2)\cdot2^2}{-8}}$

$\bf \dfrac{x-2}{-5} =\dfrac{2^{3}}{-8}}$

$\bf \dfrac{x-2}{-5} =-\dfrac{2^{3}}{2^{3}}$

$\bf \dfrac{x-2}{-5} =-\dfrac{\not2^{3}}{\not2^{3}}$

$\bf \dfrac{x-2}{-5} =-1$

$\bf x-2 =-1\cdot(-5)$

$\bf x-2 =5$

$\bf x =5+2$

$\boxed{\bf x=7}$ ∈ Ζ

Answer 2

$\frac{x-2}{(-1)^2+3*(-2)} =\frac{(-5+7)*(-2)^2}{(-2)^3} \\\\\frac{x-2}{1-6} =\frac{2*4}{-8}\\\\\frac{x-2}{-5}=\frac{8}{-8} \\\\\frac{x-2}{-5}=-1\\\\x-2=-1*( -5)\\\\x-2=5\\\\x=5+2$

⇒x=7  , 7∈Z (A)